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5.5.2 What's in an atom?

Oxygen atom gif by Sohail Sunny via https://medium.com/@sohailsunny7/bohr-atomic-theory-simple-and-easy-explanation-sohailsunny7-6bd7dab7fc3f

On this page you will explore different ideas about the structure of atoms, and what is inside them.

Inquiry questions

Factual: What are atoms made from? What are ‘fundamental’ particles? Which particles are fundamental? How do we represent the structure of atoms? 

Conceptual: How can we know what an atom is like?

Disciplinary concepts

evidence

Inquiry: How can we know what an atom is like?

Maybe you remember from the beginning of the course in 4.1.1 Powers of Ten that you explored what the Universe looked like from the very smallest to the very largest scales.

Need a reminder? Try the Powers of Ten simulation. Can you find an atom?

In the last inquiry 5.5.1 Have you ever seen an atom? you explored the evidence that atoms exist, and we saw that Brownian motion was one suggestion that there were tiny particles, invisible (then) to even the most powerful microscopes.

In 1897, the British physicist J. J. Thomson made another remarkable discovery. He was experimenting with a newly discovered ‘ray’ of energy that seemed to be produced by some metals when they were heated and given a relatively negative electric charge. Since a negative electrode is called a cathode, these rays had been called ‘cathode rays.’ But Thomson's experiments using a Cathode Ray Tube (CRT) suggested that the rays were not actually ‘beams’ of energy - as light was considered to be - but consisted of tiny, electrically charged 'corpuscles'. 

This simulation app shows you how Thomson's CRT experiment worked (there is a full experiment activity you can try later!) Try:

Controlling the accelerating voltage V_{a} at a certain value

Changing the plate voltage V_{p}. Observe how the cathode ray (electron beam) moves.

With V_{p} fixed so that the electron beam is curving, change the current I through the magnetic coils. Can you find a current that makes the electron beam straight again?

The CRT experiment showed that the cathode ray was affected by electric and magnetic fields. We now know that these ‘corpuscles’ are particles, which we call electrons because they carry a negative electrical charge. Thomson was able to use his experimental evidence to determine a value for the ratio of the charge to the mass of these particles \frac{e}{m}

The charge on the electron e = 1.6 × 10-19 Coulombs (C)

The mass of the electron m_{e} = 9.1 × 10-31 kg

Check your understanding

Sir Joseph John (J.J.) Thomson (UK, 1856 - 1940)

Drag and drop the correct physics terms to complete J.J. Thomson's description of how a Cathode Ray Tube (CRT) works.

positive cathode electrode negatively electrons magnetic deflected repelled negative current attracted 

"First I use an electric coil to warm a metal . This electrode is charged, so it is a . This causes thermionic emission of from the metal. The electrons are accelerated by attracting them to a electrode, to make an 'electron gun.' In the evacuated vessel, the electrons pass through two further metal plates. I can adjust the charge on these plates, and this caused the electrons to be . Since the electrons carry a charge, they are to the positive plate and from the negative plate. However, I can also deflect the electrons using a field. Two coils around the outside of the CRT are used to make this magnetic field. I can control the strength of the magnetic field by varying the through the coils."

Did you know that the CRT was also the basis for the (later) technology of television?


Activity 

Try the activity AC Thomson's electron beam to explore how J.J. Thomson measured the properties of the electron.

Thomson's discovery showed that there were particles even smaller than the estimated size of atoms. Thomson speculated that the electrons came from inside atoms. Since it was known that atoms were electrically neutral (did not carry a charge) unless ionised, he assumed that the rest of the atom was made from some positively charged matter, and the electrons were scattered around inside like fruit in an English ‘plum pudding.’ You can imagine a ‘plum pudding’ as a bit like a blueberry muffin!

A blueberry muffin - yum.

So how did we understand the structure of matter now? As made from solid atoms, mostly made from positively charged ‘stuff’, but with some bits of negatively-charged stuff scattered through them. If we visualised what a thin sheet of, say, gold looked like, it would look like this:

Meanwhile, the quest to measure the size of an atom continued. At the University of Manchester in 1911, two experimental physicists Hans Geiger and Ernest Marsden were working on a project with their supervisor, Ernest Rutherford. They were trying to measure the size of atoms by irradiating a thin sheet of gold (gold foil) with another new discovery, ‘alpha radiation.’ 

Image public domain via Wikipedia
Hans Geiger (left) and Ernest Rutherford with their alpha-scattering experiment at University of Manchester, UK

In the experiment, a small piece of radioactive material in a lead container was used to produce a beam of ‘alpha rays.’ The rays were directed into an evacuated vessel at a very thin gold foil. The gold foil was surrounded by a screen that was coated with Zinc Sulphide, a chemical that would produce flashes of light when the alpha rays struck it.

A replica of Geiger and Marsden's apparatus (the side is cut away to show the gold foil assembly)
Image produced using ChatGPT 5
Schematic of the Geiger-Marsden alpha-scattering experiment

Rutherford expected that the alpha rays would be deflected by the atoms in the gold foil, and they thought that they could determine the size of an atom by measuring the angles at which the flashes of light were produced by the alpha rays.

The stories about what happened next vary. Most historians think that Rutherford suggested one day that Marsden have a look to see if there were any flashes in front of the foil, where alpha particles were deflected back on their own path. If the atom was a solid ‘plum pudding’ this was thought very unlikely, because the charge of the positive ‘stuff’ was not thought to be concentrated enough to make an alpha particle go back on its tracks. Another story is that Marsden was checking the calibration of the microscope used to observe the flashes when he accidentally saw flashes occurring in front of the foil. While only about 1 in 8000 of the alpha particles were deflected in this way, it was very hard to explain with the ‘plum-pudding’ model. Rutherford commented “It was quite the most incredible event that has ever happened to me in my life. It was almost as incredible as if you fired a 15-inch shell at a piece of tissue paper and it came back and hit you.”

Expected, and observed results from the Geiger-Marsden experiment.

Check for understanding

Drag and drop the words to complete Marsden's report on his discovery of the nucleus…

nucleus angles evacuated gold foil 8000 deflection size alpha 

"The apparatus we use consists of an chamber. Inside the chamber there is a radioactive source of -particles. These particles are emitted as a beam, which we direct to strike a nearby. All around the chamber we have a luminescent screen which makes flashes of light whenever an alpha particle interacts with it. The idea is that by measuring the at which we observe these flashes, we can determine the of the alpha particles by atoms in the gold foil. From this, we can determine the of the atoms. However, one day I was observing the screen in front of the gold foil. To my astonishment, I saw occasional flashes there! Admittedly, it was only about 1 in every flashes observed, but this was very hard to explain. My supervisor Ernest Rutherford concluded that these flashes were caused by alpha particles that had interacted nearly head-on with a tiny, positively charged ."

As Rutherford put it, “It was quite the most incredible event that has ever happened to me in my life. It was almost as incredible as if you fired a 15-inch shell at a piece of tissue paper and it came back and hit you.”


Try the activity Grab-bag: Artillery shells and tissue paper to see how the alpha-scattering experiment produced such surprising results.

Inquiry:  How do we represent the structure of atoms? 

Rutherford's interpretation of the results is often referred to as ‘splitting the atom,’ because he calculated that the alpha-particles could only be deflected back on their path if they encountered a very strong positive electrical charge that repelled them. Since the overall charge on the gold atoms was already known, this suggested that the positive charge was all concentrated in the middle of the atom. In short, Rutherford, Geiger and Marsden had discovered the nucleus.

Rutherford's model of the atom.

When Rutherford ran the numbers, he realised that the nucleus was relatively tiny when compared to the atom as a whole. The atom was mostly empty space! To get a sense of this, imagine a peanut sitting on the centre-point of a soccer stadium! The peanut is the nucleus and the stadium is the atom!

Imagine a peanut in the centre of a soccer stadium… that's how tiny the nucleus is compared to the rest of the atom.

A little later, in 1913 Danish physicist Niels Bohr proposed that the electrons were organised in orbits like those of the planets around the sun. Each orbit had its own specific or quantised energy - this was the beginning of quantum physics

Oxygen atom gif by Sohail Sunny via https://medium.com/@sohailsunny7/bohr-atomic-theory-simple-and-easy-explanation-sohailsunny7-6bd7dab7fc3f
Rutherford-Bohr representation of Oxygen atom

Bohr's model is that used to visualise atoms and explain how they react chemically - although the story didn't end there…

Check for understanding

The diameter of a gold nucleus is approximately r_{n} =1.4 × 10-14 m. The atomic radius of gold is measured to be r_{a}= 0.14 nm.

Make an estimate of the size of a peanut, in metres. If the nucleus was the size of a peanut, estimate the size the whole atom would be.

\frac{r_{a}}{r_{n}}=\frac{0.14\times10^{-9}}{1.4\times10^{-14}}=10^4
Let's say a peanut nucleus is about 1 cm in diameter, or 0.005 m in radius.
So the atom would be 0.005\times10^4=50m
The atom would be about 50 metres in radius.

Assessment opportunities

Challenge and extend

Try the activity A Modelling the atom to research how our model of the atom developed further after Rutherford ‘split the atom.'


Tags: atoms, nuclei, nucleons, atomic structure, isotopes

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