P.o.t.W. #34 Solution
h\left( x \right) = ax + b h\left( {h\left( x \right)} \right) = a\left( {ax + b} \right) + b = {a^2}x + ab + b h\left( {h\left( {h\left( x \right)} \right)} \right) = a\left( {{a^2}x + ab + b} \right) + b = {a^3}x + {a^2}b + ab + b Rewrite {a^3}x + {a^2}b + ab + b as {a^3}x + b\left( {{a^2} + a + 1} \right)...