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P.o.t.W. #3 Solution

(a) domain: \(x > 0 (b) find the coordinates of the minimum point on the graph of \(g \(g'\left( x \right) = x \cdot \frac{1}{x} + \ln x = 1 + \ln x = 0\;\;\; \Rightarrow \;\;\;\ln x = - 1\;\;\; \Rightarrow \;\;\;x = {{\textrm{e}}^{ - 1}} = \frac{1}{{\textrm{e}}}...

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