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P.o.t.W. #22 Solution

\(g\left( x \right) = \sqrt[3]{x}\left( {x - 1} \right) = {x^{\frac{1}{3}}}\left( {x - 1} \right) = {x^{\frac{4}{3}}} - {x^{\frac{1}{3}}} \(g'\left( x \right) = \dfrac{4}{3}{x^{\frac{1}{3}}} - \dfrac{1}{3}{x^{ - \;\frac{2}{3}}}...

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