P.o.t.W. #2 Solution
(a) \({}_{12}{C_5} = 792 ; There are 792 ways that five different #s can be chosen from the numbers 1 to 12. (b) (i) The number of ways that three winning numbers can be chosen from the five winning numbers is \({}_5{C_3} = 10 ; and the number of ways that two non-winning numbers can be chosen from the seven non-winning numbers is \({}_7{C_2} = 21 . Thus, the number of ways that three of the five winning numbers can...