In order for the lengths of \(a\), \(b\) and 1 to form a triangle it must be true that \(a + b > 1\).If it’s true that \(a + b > 1\), then what condition must \(a\) and \(b\) satisfy so that \(a\), \(b\) and 1 are the three sides of an obtuse triangle?Applying the cosine rule: \({1^2} = {a^2} + {b^2} - 2ab\cos C\), where \(C\) is the angle between sides \(a\) and \(b\).For the triangle to be obtuse then angle \(C\) must be...