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P.o.t.W. #26 Solution

■ No GDC ■ (a) (i) \(\displaystyle\int_0^a {{x^2}{\textrm{d}}x} = \left. {\frac{1}{3}{x^3}} \right]_0^a = \frac{1}{3}{a^3} - \frac{1}{3}{0^3} = \frac{1}{3}{a^3} Q.E.D. (ii) \(\displaystyle\frac{{\textrm{d}}}{{{\textrm{d}}a}}\left( {\frac{1}{3}{a^3}} \right) = {a^2} (b) (i)...

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