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P.o.t.W. #24 Solution

■ GDC allowed ■ . . perimeter: \(a + b + c = 90\;\;\; \Rightarrow \;\;\;a + b = 90 - c Pythagorean theorem: \({a^2} + {b^2} = {c^2} similar triangles: \(\dfrac{c}{b} = \dfrac{a}{{11.25}}\;\;\; \Rightarrow \;\;\;ab = 11.25c Consider the identity \({\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab Substituting gives...

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