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P.o.t.W. #25 Solution

■ No GDC ■ Given: \(a + b = 1 and \({a^4} + {b^4} = 7 Let \(P = {a^2} + {b^2} and \(Q = ab . \({\left( {a + b} \right)^2} = 1 and \({\left( {a + b} \right)^2} = {a^2} + {b^2} + 2ab ; hence, \(P + 2Q = 1\;\;\;\; \Rightarrow \;\;\;\;P = 1 - 2Q Also, \({\left( {a + b} \right)^4} = 1 and...

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