P.o.t.W. #21 Solution
(a) \(r = \dfrac{{{u_2}}}{{{u_1}}} = \dfrac{{\;\;\dfrac{{x{{\left( {x + 1} \right)}^2}}}{{{{\left( {x - 2} \right)}^2}}}\;\;}}{{\dfrac{{x\left( {x + 1} \right)}}{{x - 2}}}} = \dfrac{{x{{\left( {x + 1} \right)}^2}}}{{{{\left( {x - 2} \right)}^2}}} \cdot \dfrac{{x - 2}}{{x\left( {x + 1} \right)}} = \dfrac{{x + 1}}{{x - 2}} (b)...