P.o.t.W. #31 Solution
2a{x^2} - 4ax + a + 1 Let {r_1} and {r_2} be the two roots. Given {r_2} = 3{r_1} Sum and product of the roots of a polynomial of the form {a_n} + {a_{n - 1}} + {a_{n - 2}} + \; \cdots \; + {a_1} + {a_0} sum \displaystyle=\frac{{ - \,{a_{n - 1}}}}{{{a_n}}}\displaystyle product {\displaystyle\displaystyle=\frac{{{{\left( { - 1} \right)}^n}{a_0}}}{{{a_n}}}}...